TypedArray.prototype.sort()
The sort()
method sorts the elements of a typed array
numerically in place and returns the typed array. This method has the same
algorithm as Array.prototype.sort()
, except that it sorts the values numerically instead of as strings by default. TypedArray is one of the
typed array types here.
Try it
Syntax
sort()
sort(compareFn)
Parameters
compareFunction
Optional-
A function that defines the sort order. The return value should be a number whose positivity indicates the relative order of the two elements. The function is called with the following arguments:
a
-
The first element for comparison. Will never be
undefined
. b
-
The second element for comparison. Will never be
undefined
.
If omitted, the array elements are converted to strings, then sorted according to each character's Unicode code point value.
Return value
The sorted typed array.
Examples
Using sort
For more examples, see also the Array.prototype.sort()
method.
let numbers = new Uint8Array([40, 1, 5, 200]);
numbers.sort();
// Uint8Array [ 1, 5, 40, 200 ]
// Unlike plain Arrays, a compare function is not required
// to sort the numbers numerically.
// Regular Arrays require a compare function to sort numerically:
numbers = [40, 1, 5, 200];
numbers.sort();
// [1, 200, 40, 5]
numbers.sort((a, b) => a - b); // compare numbers
// [ 1, 5, 40, 200 ]
Specifications
Specification |
---|
ECMAScript Language Specification # sec-%typedarray%.prototype.sort |
Browser compatibility
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